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A couple questions:

Which goes on the y axis? Radius or FT^2?

How do I ascertain the theoretical value of the slope to compare to?

Thanks,

Dystorsion

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- Thread starter dystorsion
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- #1

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A couple questions:

Which goes on the y axis? Radius or FT^2?

How do I ascertain the theoretical value of the slope to compare to?

Thanks,

Dystorsion

- #2

Dick

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What is FT^2??

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I have no clue. I'm just multiplying F with T^2.

I've done some research to help myself, though I still don't know what's going on. Here's the link I found, scroll down to the bottom for the tidbit on FT^2.

http://www.mysci.net/pages/physics1/Labs/centripetalforce.htm [Broken]

I've done some research to help myself, though I still don't know what's going on. Here's the link I found, scroll down to the bottom for the tidbit on FT^2.

http://www.mysci.net/pages/physics1/Labs/centripetalforce.htm [Broken]

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- #4

Dick

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Ok then. What are F and T^2. Sorry but I can't access links from where I am.

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---To answer the question about the axes, F goes on the y-axis and Radius goes on the x-axis; consider it as for you increase or decrease the radius, you'll retrieve another value for F.

---To explain about the situation with FT^2 being mistaken for F, is that

FT^2 = 4(pi)^2Rm, which I cant really identify (its not acceleration or the velocity). Using just F is the centripetal force, and you would graph whether F increases as the radius increases (the slope is I suppose deltaF/deltaT). Then again, I'm not exactly completely sure that this is the answer, its just I can not identify FT^2.

---If its any help...if it really is FT^2, then the slope should identify FT^2/R, in which it is equal to 4(pi)^2m; if you could find what that means, then you would be able to find out what the slope refers to.

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